Let’s look at the following example:
Train 1 leaves the train station travelling south at a rate of speed that is 10 mph more than train 2 which is travelling north. After 3 hours, they are 450 miles apart. Find the rate of train 2.
We are going to use another table to organize the rate, time and distance information.
Train | Rate | Time | Distance |
1 | r +10 | 3 | 3 (r + 10) |
2 | r | 3 | 3r |
Since the trains are moving in opposite directions, we are going to add their distances together to get 450 miles.
3 (r + 10) + 3r = 450
3r + 30 + 3r = 450
6r + 30 = 450
6r = 420
r = 70
Therefore the rate of train 2 is 70 mph.
3 comments:
Please do some Gauss Jordan problems. I need help with that!
at first i didnt kno how to do it but now i think i got it its pretty simple once u get it!
once i got to looking at these problems i got to get used to them and understood them.
-H Abbott
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